49^5x+2=(1/7)^11-x

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Solution for 49^5x+2=(1/7)^11-x equation: 



49^5x+2=(1/7)^11-x

We move all terms to the left:

49^5x+2-((1/7)^11-x)=0



Domain of the equation: 7)^11-x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

49^5x-((+1/7)^11-x)+2=0

We multiply all the terms by the denominator


49^5x*7)^11-x)-((+2*7)^11-x)+1=0

We add all the numbers together, and all the variables

49^5x*7)^11-x)-(14^11-x)+1=0

Wy multiply elements

343x^6=0

We do not support expression: x^6

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